Monday, July 30, 2012

S5 Maths Supplement :) yummy!!

Maths supplement continues ...

S5:
Mrs Brown bought some sweets for her children. If she gave each child 6
sweets, she would have 1 sweet left. If she gave each child 7 sweets, she 
would need another 4 more sweets. What is the smallest possible number of children Mrs Brown can have?

Have fun! :)
Mrs R

51 comments:

  1. My answer is 5 children.

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  2. My answer: 5 children

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  3. my answer is 5 children

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  4. I can't find the answr.Confusing. Can anyone helpfully explain? Thks

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    Replies
    1. Use the smileyface method. Or you can list out the no. of sweets and find the no. of children. But that would take alot of time.
      Add the leftover and the 'short-of': 1+4
      = 5
      Difference in no. of sweets : 7-6
      = 1
      So, no. of children ->leftover and the 'short-of'divide'Difference in no. of sweets': 5/1
      =5

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  5. 5 children. Gave birth to so much children !

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  6. wonder how she gave birth to 5 children...... Maybe she is a teacher,and those are children she teach...

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  7. Mrs Brown can have 5 children.

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  8. ???Your answers are 5. But I got 31. Why? Can someone help me to explain?

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    Replies
    1. you found the number of sweets instead of the number of children!!!!!!

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    2. Ya!You go and find the number of sweets that Mrs Brown has but not the children.

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  9. My answer is 5 children.

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  10. It is amazing that she can give birth to 5 children(My answer:5). xP

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  11. Can someone explain for me? I'm puzzled. :-(

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  12. My answer is 5 children.
    Can't get the answer from working but managed to work backwards.

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    Replies
    1. Managed to get the working.
      I won the Most Frequent Commenter on this post :-)

      Delete
  13. it is 5 children.

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  14. My answer for this question is 5 children.

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  15. Mrs Brown bought some sweets for her children. If she gave each child 6
    sweets, she would have 1 sweet left. If she gave each child 7 sweets, she
    would need another 4 more sweets. What is the smallest possible number of children Mrs Brown can have?

    1+4=5
    7-6=1
    5/1=5!
    ans:5

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  16. This comment has been removed by the author.

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  17. Total no. of sweets if arrange in 6:
    = (6xc) + 1
    Total no. of sweets if arrange in 7:
    = (7xc) - 4
    6c+1 = 7c-4
    c=5

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  18. Replies
    1. try n see whether u can understand my working

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  19. 1+4=5
    7-6=1 (difference)
    5/1=5 children

    Mrs Brown has 5 children.

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  20. 7-6=1
    4+1=5
    5/1=5

    She has 5 children.

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  21. 4+1=5
    7-6=1
    5/1=5 children

    Mrs Brown has 5 children.

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  22. 4+1=5
    7-6=1
    5/1=5

    Mrs Brown has 5 children.

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  23. 7-6=1
    4+1=5
    5/1=5

    Answer is 5 children.

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  24. 4(difference) + 1 (left) = 5
    7-6 = 1 (difference in no. of sweets)
    5/1 = 5 (Note: / means divide)
    She could have 5 children.

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  25. Mrs Roman told us that opposite sides must be added to each other.in this case, it is 4 and 1.
    So,
    4+1=5
    7-6=1(difference between the groupings)
    5/1=5

    Answer:5

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  26. M1

    7-6=1
    4+1=5
    5/1=5

    M2

    7 14 21 28 35 42 49 56 63 70
    3 10 18 25 32 39 36 53 60 67

    6 12 18 24 30 36 42 48 54 60
    7 13 19 25 31 37 43 49 55 61

    The common one is 25.
    25:
    1x25=25
    5x5=5

    So...25/5=5

    Mrs Brown can have 5 children.

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